Question

a ball is thrown upward with a velocity of 40 m/s then find (a) its velocity after 2s (b) time after which it stops (c) total time from starting if it comes back to its initial position​

Answer 1

Answer:

velocity after 2 sec.

v=40+(−10)t

=40−10∗2=20m/s

PLZ AMRK AS BRAINLIST