Question

A ball is thrown upward with a velocity of 98 m/s. Calculate
Maximum, height to which it rises
And total time it takes to return on earth​

Answer 1

Answer:

_/\_Hello mate__here is your answer--

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v = 0 m/s and

u = 98 m/s

During upward motion, g = − 9.8 m s^−2

Let h be the maximum height attained by the ball.

using

v^2 − u^2 = 2h

⇒ 0^2 − 98^2 = 2(−9.8)ℎ

⇒ ℎ =98×98/ 2×9.8 = 490 m

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Let t be the time taken by the ball to reach the height 245 m, then according to the equation of motion

v= u + gt

=>0 = 98 + (−9.8) t

⇒t 9.8 = 98

⇒ t= 98/9.8 =10s

But, Time of ascent = Time of descent

Therefore, total time taken by the ball to return

= 10 + 10 = 20s

I hope, this will help you.☺

Thank you______❤

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Explanation: