A ball is thrown upward with an essential velocity of 98 metre per second what is the maximum height attained by the object
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V = u + at
v = o u = 98 a = -g
t = 10s
s = ut -gt^2/2
s = 98*10 - 4.9*100 = 490m
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Answer:
hey mate your answer is here.........
v= u + at
v= ou = 98a = -g
t=10s
s= ut-gt ^2/2
s= 98 * 10 - 4.9* 100 = 490m.....
hope it will help you please mark the answer as brainlist and don't forget to follow me for such type of answers........
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