Question

a ball is thrown upward with an initial speed of20 meter per second calculate the maximum height attained by it​

Answer 1

Answer:

20 metres

Explanation:

v^2=u^2+2as

v=0

u=20

a=-10

s=?

0^2=20^2-2*10*s

20s=20^2

s=(20^2)/20

s=20 m