a ball is thrown upward with an initial velocity of 10m. determine the maximum height reached above the thrower's hand a) 5.25m b) 5.23m c) 5.43m d) 5.10m
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Answer:
Initail velocity
u
=
10
m
/
s
Since acceleration due to gravity is opposite to the direction of motion.
acceleration
a
=
−
g
=
−
10
m
/
s
2
At maximum height, velocity will be zero.
final velocity
v
=
0
Using the equation of motion
v
2
=
u
2
+
2
a
s
0
=
100
+
2
×
−
10
×
s
s
=
5
m
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