Question

A ball is thrown upward with an initial velocity of 20m/s. the ball is in the air for time interval

Answer 1

hello...her is your answer....
we know that v=u+at
so.....
t=v-u/a.....
here ....
u=20m/s
v=0 as at top v is 0m/s
a=-10m/s*2
So...
t=0-20/-10=2sec...
hope it helps...

pls mark brainliest if deserved
...... :D

Answer 2

$v = u + at$
$0 = 20 + ( - 9.8)t$
$0 = 20 - 9.8t$
$- 20 = - 9.8t$
$t = 20 \div 9.8$
$t = 2.04$

the ball is in air for 2.04 sec in air