Question

A ball is thrown upward with an initial velocity of 65m/s . Find out the time in which the ball will strike the ground​. Explain with each step plz​

Answer 1

Answer:

6.63 approx..

Explanation:

u= -65 m/s (because it's accerelation decreases )

v= 0

a= 9.8 m/s^2 (due to gravity)

t=?

so...

by using v=u+at

0= -65+9.8t

0+65= 9.8t

65= 9.8t

65/9.8= t

6.63 approx..= time

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