Question

A ball is thrown upward with initial velocity of 28m/s. It will reach the maximum height of ......... m.
1) 10
2) 100
3) 28
4) 40
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Answer 1

Explanation:

u = 28 m/sec, g = -9.8 m/sec², v = 0, s = ?

v² - u² = 2gs

=> 0² - 28² = 2(-9.8)s

=> - 784 = -19.6×s

=> s = -784/-19.6 => 40 m

option 4

Answer 2

Answer:

10

Initial speed =28m/s

Final velocity at maximum height =v=0m/s

a=g=10m/s²

Final answer is 10