A ball is thrown upward with speed 15 m/s find distance traveled by ball by 2 s g=9.8
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Explanation:
v=u-gt ( v=final velocity, u=initial velocity, g=acceleration due to gravity, t=time taken)
v=15-(9.8*2)
v=15–19.6
v=—4.6m/s
Also, (v^2)—(u^2)=2gh (h=total distance covered in air)
(—4.6^2)—(15^2)=2*(-9.8)*h (g is -ve cuz ball is thrown against gravity)
21.16–225=-19.6*h
h=203.84/19.6
h=10.4 m
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