Question

a ball is thrown upward with speed 40 m/s. find (i) maximum height attained by the ball. (ii) time taken to reach the maximum height. (take g = 10m/s2 )​

Answer 1

Answer:

12 metres 100p cm 40 ug pu shah a

Explanation:

due 3 x bv hhwhwj

Answer 2

Answer:

height = 80m   and

Time = 4s.

Explanation:

here, (i) $v^{2} + u^{2} = 2as$

but in free fall it became = $v^{2} + u^{2} = 2gh$

where, v = 0m/s

           u = 40m/s

           g = 10m/s

now, 0² + 40² = 2 × 10 × h

      = 1600/20 = h

      = h = 80m

∴ height = 80m

∵ v = u + gt

= 0 = 40 +(-10) × t                  [ g = -10 m/s because it is retradation force]

= -40 = -10t

= t = 4s

∴ Time = 4s

hope it will help you.