A ball is thrown upward with the speed 'u'then the speed of the ball when it is at half the highest height attended by the ball?
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Answer:
Let consider H= Maximum height
g=−10m/s
2
v=0m/s final velocity at the maximum height
u= initial velocity,
3rd equation of motion,
v
2
−u
2
=2gh
0
2
−u
2
=−2gH
u
2
=2gH. . . . . .(1)
Now, h=
2
H
and v=10m/s
3rd equation of motion,
v
2
−u
2
=2gh
10
2
−2gH=−
2
2gH
100=
2
2gH
H=
2g
100×2
H=
2×10
100×2
=10m
The correct option is 10m
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