Question

A ball is thrown upward with velocity 30 m/s.
Calculate the distance travelled by the ball in 3 s
from starting. [Take g = 10 m/s?]
(1) 30 m
(2) 45 m
(3) 60 m
(4) 75 m​

Answer 1

Answer:

Given u=30m/s

v=0

t=3s

a=-10m/s^2

s=ut+1/2at^2

=(30)(3)+1/2(10)(9)

=90-45

=45m

Answer 2

Explanation:

Initial velocity = 30m/sec

Acceleration due to gravity (g) = 10 m/sec

time (t) = 3 sec

Distance travelled =

S = ut - 1/2 gt²

S = (30 × 3) - 1/2 ( 10 × 3² )

S = 90 - 1/2 ( 90 )

S = 90 - 45

S = 45m