Question

A ball is thrown upwards at a speed of 15 metre per second what is the maximum height it reaches before falling

Answer 1

Given :

▪ A ball is thrown vertically upwards at a speed of 15m/s.

To Find :

▪ Maximum height attained by the ball.

Concept :

☞ Since, acceleration due to gravity acts continuously throughout the motion, we can easily apply equation of kinematics to solve this type of question.

☞ For a body thrown vertically upward, g is taken negative.

☞ Third equation of kinematics :

❍ v² - u² = 2as

Where,

v denotes final velocity

u dwnotes initial velocity

a denotes acceleration

s denotes distance

Calculation :

→ v² - u² = 2as

→ (0)² - (15)² = 2(-10)H

→ 0 - 225 = -20H

→ H = 225/20

→ H = 11.25m

Answer 2

Heya!!

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Given,

A ball is thrown vertically upwards at a speed of 15m/s

To Find:-

Maximum height

Now,.......

We know that , when a body thrown vertically upwards then the acceleration of the body will be negative.

so

${v}^{2} - {u}^{2} = 2as$

V =Final velocity = 0

U = Initial velocity = 15

a = acceleration = (10)

S = distance = H

${0}^{2} - {15}^{2} = 2( - 10)h$

$0 - 225 = - 20h$

$h = \frac{225}{20}$

$\underline{H=11.25m}$