a ball is thrown upwards at a speed of 28m/s find the speed of ball before reaching the maximum height in 1.8 seconds
Answers
Answered by
1
Answer:
10
v= u+ at
28-. 10×1.8
- ve since the ball is moving upward
Answered by
12
Given :
Initial velocity = 28m/s
Time taken = 1.8 sec
Accerlation due to gravity = 9.8 m/s²
To find :
The speed of ball before reaching the maximum height.
Solution :
As we are provided with initial velocity, time taken and accerlation we can use first equation of kenimatics that is,
v = u + at
where,
- v denotes final velocity
- u denotes initial velocity
- a denotes acceleration
- t denotes time
substituting all the given values in the equation,
➠ v = u + at
➠ v = (0) + (9.8)(1.8)
➠ v = 9.8 × 1.8
➠ v = 17.64 m/s
thus, the speed of ball before reaching the maximum height is 17.64 m/s.
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