Question

A ball is thrown upwards from ground with initial velocity u . ball is at height of 80 m at two times .the time interval being 6 sec .find u

Answer 1

Hello !

The initial speed = u.
The height = 80 m
Time interval = 6 seconds
Time of ascend, t1
0 = u − gt1
Time of descend, t2
u = gt2
So, t1 + t2 = 6
2u/g = 6
u= 3g
= 29. 4 m/

Thank you !

Answer 2

Heyaa☺
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Given,

Initial speed = U

Height = 80m

Time Interval = 6S

Time ascend = t

=》O = u-gt1

Time desecend,t2

=》U = gt2

T1 + T2 = 6

2U/g = 6

U = 3g//.

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