Physics, asked by ashraytiwari17, 10 months ago

A ball is thrown upwards from the ground with an initial speed of u. The ball is at a height of 80 m
at two times. The time interval being 6 s. Find u (take g = 10 m/s2).

Answers

Answered by seemasssingh4p893y4
2

Explanation:

here is your answer

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Answered by hruthik18
2

Answer:

intial velocity is 43.3 m/s

Explanation:

w.k.t

for a vertically projected body

a=+g

given

t=6

s=h=80m

u=?

by using

s=ut+1/2 at(t)

80 =6u+1/2(-10)36

80 =6u+(-180)

u=260/6

u= 43.3m/s

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