A ball is thrown upwards from the ground with an initial speed of u. The ball is at a height of 80 m
at two times. The time interval being 6 s. Find u (take g = 10 m/s2).
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Answer:
intial velocity is 43.3 m/s
Explanation:
w.k.t
for a vertically projected body
a=+g
given
t=6
s=h=80m
u=?
by using
s=ut+1/2 at(t)
80 =6u+1/2(-10)36
80 =6u+(-180)
u=260/6
u= 43.3m/s
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