A ball is thrown upwards from the surface of the moon* with a velocity of 19.6 m/s. (a) How much time will it take to attain the maximum height? (b) How high will it go?
*Make sure that you take it on the surface of a moon
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v = 0
u =19.6m/s
g = -9.8m/s/^ 2
v = u + gt
0 = 19.6 + 9.8 ( t )
-19.6/ - 9.8 = t
t = 2 s
v^ - u ^ = 2gh
0 - 9.8^ 2 =2 * -9.8 *h
9.8 *9.8 = 2*9.8 * h
h = 9.8 *9.8/ 9.8 *2
h =4.9 m
u =19.6m/s
g = -9.8m/s/^ 2
v = u + gt
0 = 19.6 + 9.8 ( t )
-19.6/ - 9.8 = t
t = 2 s
v^ - u ^ = 2gh
0 - 9.8^ 2 =2 * -9.8 *h
9.8 *9.8 = 2*9.8 * h
h = 9.8 *9.8/ 9.8 *2
h =4.9 m
harshvarmasmhs:
Even if I mentioned that g should be taken as that of moon the also....
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