Question

a ball is thrown upwards with a speed of 10m/s
calculate height attained and time taken to reach there
g = 10 m/s

Answer 1

I have solved this in a paper. Please look at the attachment.

Answer 2

$\huge \orange{ \overbrace{ \red{\underbrace \color{blue} {\underbrace \color{black}{\colorbox{lime}{ {\red \: {☘Answer ☘ }}}}}}}}$

Given ,

Initial velocity (u) = 10m/s

Acceleration due to gravity = 10m/s²

________________________

i) Height it reaches :-

Using ,

♦ H = u²/2g

Here ,

u = 10m/s

g = 10m/s²

H = ?

⇒ H = 10²/2(10)

⇒ H = [ 100/20 ]

⇒ H = 10/2

⇒ Height = 5m

________________________

ii) Time taken to return back :-

Using ,

♦ v = u + gt

Here ,

v = 10m/s

u = 0m/s [since it starts from rest when it is in air for some time ]

g = 10m/s²

t = ?

⇒ 10 = 0 + 10 × t

⇒ 10 = 10t

⇒ t = 10/10

⇒ Time = 1s

Time cannot be negative

⇒ Time = 1s