Question

A ball is thrown upwards with a speed of 30 m/s it return back to the hands of the thrower after 6sec calculate maximum height attained by the ball if the acceleration is 10m/s^2

Answer 1

initial velocity (u) =30m/s
time(t)=6/2=3sec
final velocity (v) =0m/s
acceleration =10m/s²
height =ut + 1/2 * at²
=30*3+1/2*10*3²
=90+45
=145 m