Question

a ball is thrown upwards with a velocity of 49 m/s and g= 9 m/s . calculate the maximum height it rises upto?​

Answer 1

Answer:

Explanation:Given Initial velocity of ball, u=49 m/s

Let the maximum height reached and time taken to reach that height be H and t respectively.

Assumption: g=9.8 m/s  

2

 holds true (maximum height reached is small compared to the radius of earth)

Velocity of the ball at maximum height is zero, v=0

v  

2

−u  

2

=2aH                          

0−(49)  

2

=2×(−9.8)×H          

⟹H=122.5 m                

v=u+at

0=49−9.8t            

⟹t=5 s

∴ Total time taken by ball to return to the surface, T=2t=10 s