Question

A ball is thrown upwards with an intial velocity of 20 m/s calculate the nett displacement & total distance covered by it when it reaches the earth surface take g =10m/s​

Answer 1

Answer:

According to the equation of the motion under gravity

v

2

−u

2

=2gs

u=initial velocity of the stone=40m/s

v= Final velocity of the stone=0m/s

Let h be the maximum height attained by the stone

Therefore,

0

2

−40

2

=2(−10)h

h=(40×40)/20=80

Therefore, total distance covered by the stone during its upward and downward journey=80+80=160m

Net displacement during its upward and downward journey=80+(−80)=0

Explanation: