A ball is thrown upwards with speed 10m/s from the top of tower reaches ground with a speed 20m/s.Find the height of the tower
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94
V^2 = U^2 + 2AS
v = 20 m/s
u = 0 m/s (velocity at highest point)
It implies,
400 = 0+ (2 * 10 * s)
400 = 20s
s = 20m (total distance covered by rock while going down from its highest point)
V^2 = U^2 + 2AS
0 = (10^2) + (2*-10*s)
100 = 20s
s = 5 (distance covered by stone when thrown up with an intital velocity of 10m/s)
Therefore tower is 20-5 = 15m tall.
v = 20 m/s
u = 0 m/s (velocity at highest point)
It implies,
400 = 0+ (2 * 10 * s)
400 = 20s
s = 20m (total distance covered by rock while going down from its highest point)
V^2 = U^2 + 2AS
0 = (10^2) + (2*-10*s)
100 = 20s
s = 5 (distance covered by stone when thrown up with an intital velocity of 10m/s)
Therefore tower is 20-5 = 15m tall.
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25
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