a ball is thrown upwards with velocity 10m/s after 1 second what is its height
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given:
initial velocity = 10m/s (u)
final velocity = 0m/s(v)
acceleration = -10m/s² ( by v - u/t )
time = 1 sec
height = s
using v² - u² = 2as
0 - 100 = 2 × -10 × s
-100/-20 = s
s = 5m
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