Question

A BALL IS THROWN UPWORDS IN VACUM WITH A SPEED OF 49M/S THE TIME TAKEN BY IT TO REACH THE HEIGHEST POINT

Answer 1

Explanation:

At highest point, velocity, v = 0 m/s and acceleration, a = -g = -9.8 m/s^2. Initially the velocity, u = 49 m/s. Therefore, 0 = 49 - 9.8t => t = (-49)/(-9.8) = 5 seconds