a ball is thrown velocity downwards with velocity u from a height h find the striking time of the ball
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Explanation:
Initial energy E
i
=PE+KE=mgh+
2
1
mv
2
Energy when it reaches the ground: E=
2
1
mv
′2
since PE is zero.
Given, E=
2
1
E
i
Since it rises to the same height E
f
=mgh+0 is the final energy
⇒
2
1
(mgh+
2
1
mv
2
)=E
f
=mgh+0
v
2
=2gh=2×10×20=20
2
⇒v=20m/s
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