A ball is thrown vertical upward at the reaches at height 90 m find the velocity with which it was thrown
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Answer:
42 m/s
Explanation:
Let initial velocity with which ball was thrown upwards be u m/s
Final velocity as it reaches top height of 90 m is 0 m/s
acceleration due to gravity = -9.8 m/(s)^2
Using formula
(v)^2 - (u)^2 = 2(-g)h
0 - (u)^2 = 2×(-9.8)×90
(u)^2 = 1764
u = √1764
u = 42 m/s
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