Physics, asked by achalnikhade2004, 6 months ago

A ball is thrown vertically dawnword with velocity of 20 m/s from the top of tower it hits the ground after some time with velocity of 8m/s the hieght of the tower is​

Answers

Answered by gayathrikoritala
2

Explanation:

so here u=20m/s,v=8m/s,g=10m/s

first find "t" through equation v=u+at

8=20+10*t

8-20=10*t

-12=10*t

t=-12/10

t=-6/5s

now find height by S=ut+1/2at²

S=20*-6/5+1/2 *10*36/25

S=-24+36/5

S=-24+7.2

S=-16.2m

so height of the tower is -16.2m

Similar questions