A ball is thrown vertically dawnword with velocity of 20 m/s from the top of tower it hits the ground after some time with velocity of 8m/s the hieght of the tower is??
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Answer:
The distance covered is given as
s
1
=20t+5t
2
s
2
=30t−5t
2
s
1
+s
2
=150⇒150=50t⇒t=3s
Hence, the time after which both the balls will meet is 3 s.
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