A ball is thrown vertically dawnword with velocity of 20 m/s from the top of tower it hits the ground after some time with velocity of 8m/s the hieght of the tower is??
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16.8m
Explanation:
a= (-g)
v=8m/s
u=20m/s
v²=u²+2as
in this case since a=(-g)
v²=u²-2gs
8²=20²-2×10×s
64=400-20s
20s=400-64
20s=336
s=336/20
s=16.8m
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