Question

A ball is thrown vertically downward with a
velocity of 20 m/s from the top of a tower. It hits
the ground after some time with a velocity of
80 m/s. The height of the tower is : (g= 10 m/s2​

Answer 1

Answer:

ANSWER :

• H=30M

The initial velocity of the ball is =20 m/s.

The final velocity of the ball is =80 m/s.

The acceleration due to gravity is =10 m/s².

So, the height of the tower can be obtained from the expression:

v²=u²+2gh

Substitute the values in above expression:

80²=20² x (2x10 x h)

h=$\frac{6400 - 400}{20}$

h =$\frac{6000}{20}$

h=30m.

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Answer 2

Answer:

The initial velocity of the ball is =20 m/s.

The final velocity of the ball is =80 m/s.

The acceleration due to gravity is =10 m/s².

So, the height of the tower can be obtained from the expression:

v²=u²+2gh

Substitute the values in above expression:

80²=20² x (2x10 x h)

h= \frac{6400 - 400}{20}

20

6400−400

h = \frac{6000}{20}

20

6000

h=30m.

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Explanation:

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