A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is :
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Answer:
300 m
Explanation:
The initial velocity of the ball is =20 m/s.
The final velocity of the ball is =80 m/s.
The acceleration due to gravity is =10 m/s2.
So, the height of the tower can be obtained from the expression:
v2=u2+2gh
Substitute the values in above expression:
802=202+(2×10×h)
h=206400−400 m
h=206000⇒300 m
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Answered by
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Answer:
The height of the tower is :300m
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