A ball is thrown vertically downwards from a height of 20m with an initial velocity v0. It collides with the ground, loses 50 percent of its energy in collision and rebounds to the same height. The initial velocity v0 is : (Take g = 10ms–2)
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20 m s-1 Explanation: The situation is shown in the figure. Let v be the velocity of the ball with which it collides with ground. Then according to the law of conservation of energy, Gain in kinetic energy : loss in potential energy Now, when the ball collides with the ground, 50% of its energy is lost and it rebounds to the same height h. Substituting this value of * in eqn. (i), we get Read more on Sarthaks.com - https://www.sarthaks.com/229814/a-ball-is-thrown-vertically-downwards-from-a-height-of-20-m-with-an-initial
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