Question

a ball is thrown vertically in upward direction if t=2 and g=9.8m then find its maximum height​

Answer 1

Answer:

s = ut + 1/2 gt^2

= 0m/s * 2s + 1/2 * 9.8m/s^2 * ( 2 )^2s

= 1/2 * 9.8m/s^2 * 4s

= 4.9 * 4 m

= 19.6m

hope it helps you ................

Answer 2

Answer:

I got it 19.6m

Explanation:

I am not sure though... but the explanation is here:

u = 0 (the ball is thrown from it's resting position)

t = 2

a = -9.8

By the equation of motion;

s = ut + 1/2 at²

s = 0x2 + 1/2x-9.8x2x2

s = -9.8 x 2

s = -19.6m

By convention it is 19.6 metres.

Hope it was helpful.