A ball is thrown vertically of wall with speed 20 metre per second from a tower speed of the particle at t = 1 second and t = 3 second
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"Initial velocity u = 20 m/s
Time (t) = 5 sec
Distance (s) = ?
Final velocity (v) = ?
G = 9.8 m/s^2
As per the formula,
S = -ut + 1/2 at^2
S = -20 * 5 + ½ * 9.8 * 5^2
S = -100 + 122.5
S = 22.5 m
And,
V = -u + gt = -20 + 9.8 * 5= -20 + 49 m/s = 29 m/s
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