A ball is thrown vertically up from top of a tower
of height 35 m with speed of 30 m/s. By what
speed it will hit the ground?
Answers
Answered by
5
Answer:10√7
Explanation:
as we know speed before hitting the ground (v)=√2gh. So by using the given value we can calculate this
height (given)=35m
g=10
so use formula
v=√2×10×35=10√7
Answered by
2
Answer:40 m/s
Explanation:
Ball is thrown upwards,So
v=0
u=30m/s
v²=u²-2gh
0=30×30-2×10×h
h=900÷20
h=45m(Distance travelled by ball upwards)
Total distance travelled before hitting ground:35+45=80m
So
u=0
h= -80m
Speed by which it hits the ground-
v²=u²-2gh
v²=0-2×10×-80
v=√1600
v=40m/s
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