Question

A ball is thrown vertically up ward with a velocity of 40m/sec, then what is the maximum height attained by the ball and the time taken by the ball to reach that
height. If acceleration due to gravity is 10m/s²
​

Answer 1

Explanation:

Maximum height reached by the ball is given by the formula

${u}^{2} \div 2g$

So by putting the value of u in expression we get

40*40=1600

1600/2g

80 metre

Time taken is given by

U/g

So 40/10=4

4 seconds

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