a ball is thrown vertically up with valocity of 50 ms from point A on the ground . another ball is dropped after 2 sec vertically downward with valocity of 20 ms from B directly above point A at a height of 200 m above ground. when and where the two balls cross each other ( kindly solve it completely and give it to me )
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Answer:
velocity 50 ms
50×2=100
speed = distance × time
Explanation:
so u need to find time
good luck , solving
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