Question

A ball is thrown vertically upward and attains a maximum height 20m.
then calculate: i) initial velocity of the ball
ii) time taken to reach the maximum height​

Answer 1

Answer:

Step-by-step explanation:

The velocity of the projection is given as,

$\large\tt v^2 = u^2+2as$

$\large\tt u=\sqrt{2×10×20}$

$\large\tt =20\:m/s$

$\large\tt s=ut+\dfrac{1}{2}at^2$

$\large\tt s=0\: \: \: \: \: \:u=20\: \: \: \: \:a=-10$

$\large\tt t=20×\dfrac{20}{10}$

$\large\tt =4s$