Question

A ball is thrown vertically upward and return to thrower after 6sevonds find the velocity with which it was thruown up

Answer 1

it means that time of flight =6sec
T=2u/g......... (u=initial velocity,g=10m/s^2)
6=2u/10
6×10=2u
60/2=u
u=30m/s

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Answer 2

30m/s (when we take g=10 m/s^2)

When the ball is at the highest point it can reach,

V=0

U=?

t=3

V=U+at

0=U-30

U=30m/s