A ball is thrown vertically upward and rises to a height of 126.5 m
1) calculate the velocity by which the ball was thrown upward
2) the time taken by the ball to reach the highest point.
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Explanation:
2) the time taken by the ball to reach the highest point
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Let velocity of object is u
we know, at 126.5m height object will be rest .
so, final velocity = 0
A/C to kinematics equations,
v² = u² + 2aS
v² = u² +2(-g) × h
0 = u² - 2 × 9.8 x 126.5
u² = 2,479.4
u = √2,479.4
= 49.79 m/s
= 50 m/s
Time taken by the object to reach the highest point is t
v = u + at
0 = 49.79 - 10t
t = 50/10 sec
t = 5 sec
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