Question

A ball is thrown vertically upward from a ground with speed of 40m/sc.It collides with ground after returning. Find the total distance travelled and time taken during its bouncing.

Answer 1

➡️Total distance covered by ball from going max height to ground is '2s'

s- Distance travelled to complete one journey

$using \: equation \: of \: motion - \\ {v}^{2} - {u}^{2} = - 2gs \\ - {(40)}^{2} = - 2gs \\ - 160 = 2s \\ s = 80m$
➡️Total journey distance–» 80×2=160metres.

Time taken to complete 2s will be twice as for s

so,
$v = u - gt \\ 0 = 40 - 10t \\ - 40 = - 10t \\ t = 4sec$
Total time taken to reach ground again after launching is$\boxed{\red{ 8seconds}}$

Answer 2

plz refer to the attachment..

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