A ball is thrown vertically upward from ground with speed 40m per sec. It collides with ground after returning
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Total distance covered by ball from going max height to ground is '2s'
s- Distance travelled to complete one journey
➡️Total journey distance–» 80×2=160metres.
Time taken to complete 2s will be twice as for s
so,
v= u - gt
0= 40 - 10t
-40= -10t
t = 4 seconds
Total time taken to reach ground again after launching is 8 seconds
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