Question

A ball is thrown vertically upward from the foot of a 10 m high tower with such a initial velocity that it may just reach to its top. What was the initial velocity of a ball. (g=9.8m/s2)

Answer 1

u=10m/s , v=0 , g =9.8 m/s^2 , h= !

v^2= u^2 - 2.g.h

(0)^2= (10)^2 - 2×9.8×h

19.6×h=100

h = 100/19.6 m.

h= 5.102 m. (answer)