Question

A ball is thrown vertically upward from the ground, it crosses a point at a height of 60m twice at an interval of 4 second. Find the velocity with which the ball hits the ground.

Answer 1

Answer:

30m/s

Explanation:

At the point 25m above it takes 4 sec. i.e., time of flight there is 4 s.

4 = 2u/g

u=20m/s

at 25m height it has velocity 20m/s and it goes further height of u2/g=20m

Total max height =20+25=45m

Initial velocity.

45= u2/2g

u=30m/ s

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