a ball is thrown vertically upward from top of tower with speed of 100m/s .it strikes the pong near the base of the tower after 25s .the height of the tower is?
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We are given
velocity=-100
negative because its opposite the direction of motion.
and t=25sec
By using the formula..
h=ut + 1/2 at^2
h=(-100)(25) +1/2(10)(25^2)
h=-2500+3125
h=625m
velocity=-100
negative because its opposite the direction of motion.
and t=25sec
By using the formula..
h=ut + 1/2 at^2
h=(-100)(25) +1/2(10)(25^2)
h=-2500+3125
h=625m
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