Question

A ball is thrown vertically upward it has a speed of 10 metre per second when it has reached one half of its maximum height how high does the ball rise ​

Answer 1

$\LARGE\underline{\underline{\sf \red{Given}:}}$

• Ball is thrown vertically upward = 10m/s

$\LARGE\underline{\underline{\sf \red{To\:Find}:}}$

• How high does the ball rise.

$\LARGE\underline{\underline{\sf \red{Solution}:}}$

From 3rd Equation of motion :

$\large{\boxed{\sf v^2=u^2-2gs }}$

v = final velocity = 0 at highest point

u = initial velocity = 10m/s

g = 10m/s²

$\implies{\tt 0 =(10)^2-2×10×\dfrac{h}{2}}$

$\implies{\tt 0=100-10h }$

$\implies{\tt 10h=100 }$

$\implies{\tt h=\dfrac{100}{10} }$

$\implies{\tt h = 10m }$

$\LARGE\underline{\underline{\sf \red{Answer}:}}$

•°• When it has reached one half of its maximum height 10m high the ball rise .