Question

A ball is thrown vertically upward. it has a speed of 10m/s when it has reached one half of its maximum height. How high does the ball rise​

Answer 1

Answer:

From third equation of motion ,v

2

=u

2

−2gh

0=u

2

−2g(h/2)

h=

g

u

2

=

10

10

2

=10m

Thus, the ball rises to 10m

solution

Answer 2

Explanation:

From 3rd equation of motion v2 = u2 - 2gH

0=u^2-2g (H/2)=u^2-gH

H= u^2/g= ?10?^2/10 =10 m

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