Question

A ball is thrown vertically upward. It returns back to the surface of the earth after reaching the maximum height .(i) find the total distance travelled by the stone. (ii) find the displacement of the stone .​

Answer 1

Explanation:

Given that Initial velocity, u = 40 m/s, Final velocity, v = 0 m/s.

Acceleration due to gravity, g = 10m/s2(downward motion).

Maximum height, s = H.

As the body is thrown upward a = -g the relation v2=u2−2as gives v2=u2−2aH, we have,

H = 2gu2−v2=2(10m/s2)40m/s2−02=201600=80m.

If a stone is thrown vertically upward, it returns to its initial position after achieving maximum height.

so, the net displacement = Difference of positions between initial and final positions = 0.

Total distance covered = 80 m + 80 m = 160 m.

Hence, the displacement is 0 and the total distance covered is 160 m.

PLEASE MARL AS THE BRAINIEST

Answer 2

Pls see the attachment...I think this would be correct answer.....