Question

a ball is thrown vertically upward, prove that the it's time of ascent is equal to the time of descent

Answer 1

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Time of Ascent is the time taken by ball thrown upto reach maximum height h

Let t₁ be time of ascent.

At maximum height, its velocity is zero, V=0

Hence, v=u-gt

0=u-gt₁

t =u/g ------------- (1)


Time of descent : After reaching the maximum height, the ball begins to travel downwards and reaches the ground. The time taken to by a freely falling ball to touch the ground is called time of descent.


Initial velocity for downward journey is zero, u= 0


let t₂ be time of descent.

s=ut+1/2 gt²

h=0+1/2gt₂²

t =√2h/g

But, h=u²/2g

so, we get

t₂=√2u²/2g

=u/g---------------(2)

From equation 1 and 2, we see t₁=t₂


The time of ascent is equal to time descent if the ball is thrown vertically upwards.



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Answer 2

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