Question

A ball is thrown vertically upward with 20 ms-1

standing on the roof of his house 10 m high.

Calculate the time after which the ball will hit the ground. (take g = 10 ms-2

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Answer 1

Answer:

4.45s

Explanation:

u=+20m/s

S(displacement)=-10m

g=-10m/s^2

(we are taking upward direction as positive)

So now,

S=ut+1/2gt^2

-10=20t-5t^2

-2=4t-t^2

t^2-4t-2=0

So,t=4.45s

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Hope it helps